35=4x-x^2

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Solution for 35=4x-x^2 equation:


Simplifying
35 = 4x + -1x2

Solving
35 = 4x + -1x2

Solving for variable 'x'.

Reorder the terms:
35 + -4x + x2 = 4x + -4x + -1x2 + x2

Combine like terms: 4x + -4x = 0
35 + -4x + x2 = 0 + -1x2 + x2
35 + -4x + x2 = -1x2 + x2

Combine like terms: -1x2 + x2 = 0
35 + -4x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-35' to each side of the equation.
35 + -4x + -35 + x2 = 0 + -35

Reorder the terms:
35 + -35 + -4x + x2 = 0 + -35

Combine like terms: 35 + -35 = 0
0 + -4x + x2 = 0 + -35
-4x + x2 = 0 + -35

Combine like terms: 0 + -35 = -35
-4x + x2 = -35

The x term is -4x.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4x + 4 + x2 = -35 + 4

Reorder the terms:
4 + -4x + x2 = -35 + 4

Combine like terms: -35 + 4 = -31
4 + -4x + x2 = -31

Factor a perfect square on the left side:
(x + -2)(x + -2) = -31

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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